06-09-2024 11:45 AM
Solved! Go to Solution.
06-10-2024 06:44 AM - edited 06-10-2024 06:45 AM
In an SPBm network ALL TRAFFIC will take the shortest path on a physical links between BCBs and BEBs.
However, in a situation where there is a symmetrical equal path between BCBs and BEBs traffic will get balanced across the links.
However, the necessity to balance over more than 2 BVLANs is redundant because the equal path vector can only ever be over two links. Balancing over more than 2 BVLANs really gives you nothing.
06-10-2024 08:09 AM
@EXTR_Paul @Shaja I have been thinking. Is the BVLANs only for BUM traffic? And Once the destination MAC address is learned (meaning that the destination BEB is known for the Customer MAC), it will use all available paths for sending the packet? Thanks.
06-11-2024 04:47 AM
It will always take the shortest path, when there are equal cost paths, then traffic is load balanced.
06-15-2024 09:10 AM
Hi Willy, let's say that the destination c-MAC is learned and it is on a BEB with a b-MAC. There are three equal-cost paths to the b-MAC. Can it load balance on all three paths? Is there a command to list all equal-cost paths to a c-mac? Thanks!
06-10-2024 06:44 AM - edited 06-10-2024 06:45 AM
In an SPBm network ALL TRAFFIC will take the shortest path on a physical links between BCBs and BEBs.
However, in a situation where there is a symmetrical equal path between BCBs and BEBs traffic will get balanced across the links.
However, the necessity to balance over more than 2 BVLANs is redundant because the equal path vector can only ever be over two links. Balancing over more than 2 BVLANs really gives you nothing.